121-16t^2=0

Solution for 121-16t^2=0 equation:

121-16t^2=0

a = -16; b = 0; c = +121;
Δ = b2-4ac
Δ = 02-4·(-16)·121
Δ = 7744
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7744}=88$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-88}{2*-16}=\frac{-88}{-32}
=2+3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+88}{2*-16}=\frac{88}{-32}
=-2+3/4
$